NodeTimeoutError
If you pasted that class name into a search box, one node in your LangGraph graph ran longer than a timeout someone set on it. This is not the graph-wide step limit and not a clock on the whole run. It is a per-node clock, and it comes in two kinds. Below: what the vendor’s docs say it is, read off them today, where the timeout is set, which of the two clocks fired, and the fix for each.
LangGraph’s API reference, at
reference.langchain.com/
Raised when a node invocation exceeds one of its configured timeouts.
“One of its” is the useful part: a node can carry two timeouts. The same page lists the attributes node, elapsed, kind, timeout, run_timeout and idle_timeout, with kind typed Literal['idle', 'run'], and says:
Both idle_timeout and run_timeout reflect the configured policy at the time of the failure (each is None if not configured). kind and timeout identify which one fired.
So the exception already tells you which node, which clock and how many seconds had passed. Read those before you change any number.
LangGraph’s fault-tolerance guide, at
docs.langchain.com/
The guide also says node timeouts apply only to async nodes, that sync nodes with a timeout are rejected at compile time, and that per-node timeouts require langgraph>=1.2.
If both are set, the guide says “Whichever fires first cancels the attempt.” When one fires, LangGraph “clears any writes from the failed attempt, and lets the retry policy decide whether to retry.” The error handler, if any, runs only after retries are exhausted, or straight away if no retry policy is set.
Catch it by name and read it.
from langgraph.errors import NodeTimeoutError try: await graph.ainvoke(inputs, config) except NodeTimeoutError as e: print(e.node, e.kind, e.elapsed, e.run_timeout, e.idle_timeout) raise
Use except NodeTimeoutError, not except TimeoutError. The two vendor pages
disagree here: the errors reference says the class “Does not inherit from the built-in
TimeoutError (a subclass of OSError) so that the default RetryPolicy treats it as retryable”,
while the graph-API guide, at
docs.langchain.com/
If kind is "run": the node needed more time than you gave it. Compare elapsed with what the work really needs. Then either raise run_timeout on that node or split the work so that one attempt does less. An idle setting will not help here, because nothing refreshes this clock.
If kind is "idle": the node did work that LangGraph could not see. The guide’s answer for long work that “doesn’t naturally emit progress signals” is to call runtime.heartbeat() as it goes:
async def long_running_node(state: State, runtime: Runtime) -> State: for batch in fetch_batches(): process(batch) runtime.heartbeat() return {"result": "done"}
The guide adds that runtime.heartbeat() is a no-op outside an idle-timed attempt, so you can call it unconditionally.
Retry instead of failing, if a fresh attempt can succeed. The guide says NodeTimeoutError is retryable by default. With a retry policy on the node, such as retry_policy=RetryPolicy(max_attempts=3), “the timeout clock resets on each new attempt, and writes from a timed-out attempt are cleared before the next retry.”
One thing that looks like a timeout bug but is not: the TimeoutPolicy reference says timeouts rely on asyncio cancellation, and that if a node uses synchronous time.sleep() or other CPU-bound work that blocks the GIL, “the timeout will not be fired until after the event loop has been released.” The fault-tolerance guide’s advice for blocking I/O is asyncio.to_thread inside an async node. So if elapsed is well past the limit you set, look for blocking code in that node.
The errors reference, at
reference.
There is a written guide: the step-and-turn arithmetic as a formula you can run against a brief before you launch it, why raising a cap does not finish the job, and batch.py, one standard-library file that collapses a per-item loop into a single pass. It is $19, on a Gumroad storefront. One working way to pay today is 19 USDC on Base: you email the transaction hash and the guide is delivered by email. This page is free, ungated, and sells nothing on its own.
The short version: NodeTimeoutError is, in LangGraph’s own words, “Raised when a node invocation exceeds one of its configured timeouts.” The timeout lives on add_node, set_node_defaults, a Send, or @task/@entrypoint. Read e.kind. If it is "run", the attempt outran a hard cap: raise run_timeout or split the work. If it is "idle", the node showed no progress: call runtime.heartbeat() during long work. Add a RetryPolicy if a fresh attempt can succeed. Catch it as NodeTimeoutError, not TimeoutError.
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